C hicken and rabbit s

code

6 年前

时间： 1ms 内存：32M

描述：

Chicken and rabbits are in a same cage. As we all know, chicken has two legs but rabbit has four. Now

we know the number of legs in the cage is A, please tell me how many animals may in the cage at least

and at most.

输入：

The first line of the input contains the number of test cases in the file. Each test case that follows

consists of one lines. each case contains only one integer numbers A specifying the total legs in the

cage .

输出：

For each test case, print a line contains the answer

示例输入：

2
3
20

示例输出：

0 0
5 10

提示：

参考答案（内存最优[1092]）：

#include<stdio.h> 
int main() 
{ 
     int n; 
    scanf("%d",&n); 
    while(n--) 
    { 
        long long m; 
        scanf("%lld",&m); 
        if(m%2==1) 
        { 
            printf("0 0\n"); 
            continue;  
        }    
        if(m%4==0) 
        printf("%lld ",m/4); 
        else
        printf("%lld ",m/4+1); 
        printf("%lld\n",m/2); 
    } 
    return 0; 
    }

参考答案（时间最优[0]）：

#include<stdio.h>
#include<string.h>
int main()
{
    int n;
    int total;
    int a=0,b=0;
    scanf("%d",&n);
    getchar();
    while(n>0)
    {
        scanf("%d",&total);
        if(total%2!=0)
        {
            a=0;b=0;
        }
        else if(total%4!=0)
        {
            a=(total-2)/4+1;b=total/2;
        }
        else
        {
            a=total/4;b=total/2;
        }
        printf("%d %d\n",a,b);
        n--;
    }
    return 0;
}

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